已知(x-3)^2+丨3y+1丨=0.求3x^2y-[2xy-2(xy-3/2)+xy]+3xy^2的值
问题描述：
已知(x-3)^2+丨3y+1丨=0.求3x^2y-[2xy-2(xy-3/2)+xy]+3xy^2的值
答
(x-3)^2+丨3y+1丨=0x-3=0,3y+1=0x=3,y=-1/33x^2y-[2xy-2(xy-3/2)+xy]+3xy^2=3x^2y-2xy+2xy-3-xy+3xy^2=3x^2y-xy+3xy^2-3=3*9*(-1/3)-3*(-1/3)+3*3*(-1/3)^2-3=-9+1+1-3=-10