计算:1−1/2+1/3−1/4+…+1/1997−1/1998+1/19991/1+1999+1/2+2000+1/3+2001+…+1/999+2997+1/1000+2998.
问题描述:
计算:
. 1−
+1 2
−1 3
+…+1 4
−1 1997
+1 1998
1 1999
+1 1+1999
+1 2+2000
+…+1 3+2001
+1 999+2997
1 1000+2998
答
分子=(1+
+1 2
+1 3
+…+1 4
+1 1997
+1 1998
)−2×(1 1999
+1 2
+1 4
+…+1 6
),1 1998
=(1+
+1 2
+…+1 3
)−(1+1 1999
+1 2
+…+1 3
),1 999
=
+1 1000
+…+1 1001
;1 1999
分母=
+1 2000
+1 2002
+…+1 2004
+1 3996
1 3998
=2×(
+1 1000
+…+1 1001
);1 1999
原式=
=
+1 1000
+…+1 1001
1 1999 2×(
+1 1000
+…+1 1001
)1 1999
.1 2