计算;(1+x)(x的2次方+x分之x-1-x的3次方-x分之1-x)

问题描述:

计算;(1+x)(x的2次方+x分之x-1-x的3次方-x分之1-x)

(1+x)[(x-1)/(x^2+x)-(1-x)/(x^3-x)]
=(1+x)[(x-1)/x(x+1)+(x-1)/x(x-1)(x+1)]
=(1+x)(x-1)/x(x+1)+(1+x)(x-1)/x(x-1)(x+1)
=(x-1)/x+1/x
=(x-1+1)/x
=x/x
=1