求x²-(p²+q²)x+pq(p+q)(p-q)和x²-2xy-8y²-x-14y-6因式分解
问题描述:
求x²-(p²+q²)x+pq(p+q)(p-q)和x²-2xy-8y²-x-14y-6因式分解
答
x²-(p²+q²)x+pq(p+q)(p-q﹚=[x-q﹙p+q﹚][x-p﹙p-q﹚]
x²-2xy-8y²-x-14y-6=﹙x+2y+2﹚﹙x-4y-3﹚
交叉相乘法.