计算:(−1/2xy2)2(3xy−4xy2+1).

问题描述:

计算:(−

1
2
xy2)2(3xy−4xy2+1).

(-

1
2
xy22(3xy-4xy2+1)
=
1
4
x2y4(3xy-4xy2+1)
=
3
4
x3y5-x3y6+
1
4
x2y4