已知4^m=8,16^n=6,求4^(2m-4n+1)的值
问题描述：
已知4^m=8,16^n=6,求4^(2m-4n+1)的值
答
4^(2m-4n+1)
=(4^2m)/(4^4n)*4
=4*(4^m)^2/(16^n)^2
=4*8^2/6^2
=64/9