4xy+1-4x^2-y^2= x^6-y^6-2x^3+1= x^4+64= x^3-4xy^2-2x^2y+8y^3=
问题描述：
4xy+1-4x^2-y^2= x^6-y^6-2x^3+1= x^4+64= x^3-4xy^2-2x^2y+8y^3=
答
我高中数学老师、应该是这样没错4xy+1-4x^2-y^2=1-(4x^2-4xy+y^2)=1-(2x-y)^2=(1+2x-y)(1+y-2x)x^6-y^6-2x^3+1= x^6-x^3-x^3+1-y^6=x^3(x^3-1)-(x^3-1)-y^6=(x^3-1)^2-y^6=(x^3-1-y^3)(x^3-1+y^3)x^4+64=x^4+16x^2+6...