a方-2a分之a+3-a分之1÷9-a方分之2-a

问题描述:

a方-2a分之a+3-a分之1÷9-a方分之2-a

原式=a/a(a-2)+1/(3-a)×(9-a²)/(2-a)
=1/(a-2)-1/(a-3)×(a+3)(a-3)/(a-2)
=1/(a-2)-(a+3)/(a-2)
=(1-a-3)/(a-2)
=-(a+2)/(a-2)