F-(M+m)g=(M+m)a ····················☆

问题描述:

F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2(m+M)〕/M
F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2f(m+M)〕/M

(1)得F=(M+m)(g+a)
(2)得2f=M(g+a) (g+a)=2f/M
代入得
F=2f(M+m)/M