tana=1/2,tanb=1/3,tan(a+b)=
问题描述:
tana=1/2,tanb=1/3,tan(a+b)=
答
tan(a+b)=(tana+tanb)/(1-tanatanb)=(1/2+1/3)/(1-1/6)=1
tana=1/2,tanb=1/3,tan(a+b)=
tan(a+b)=(tana+tanb)/(1-tanatanb)=(1/2+1/3)/(1-1/6)=1