求函数f(x)=sin(4x+π/3)+cos(4x-π/6)的周期

问题描述:

求函数f(x)=sin(4x+π/3)+cos(4x-π/6)的周期

f(x)=sin(4x+π/3)+cos(4x-π/6)
=sin(4x-π/6+π/2)+cos(4x-π/6)
=cos(4x-π/6)+(4x-π/6)
=2cos(4x-π/6)-1+1
=cos(8x-π/3)+1

=>T=2π/8=π/4