x²-x-1=0,求-x³+2x²+2011
问题描述:
x²-x-1=0,求-x³+2x²+2011
答
x²-x-1=0,
x²-x=1,
-x³+2x²+2011
=-x³+x²+x²+2011
=-x(x²-x)+x²+2011
=-x+x²+2011
=x²-x+2011
=1+2011
=2012