(1) a3-2a2+a (2)ax2-8ax+16a (3)a3b-2a2b2+ab3 提取公因式,
问题描述:
(1) a3-2a2+a (2)ax2-8ax+16a (3)a3b-2a2b2+ab3 提取公因式,
答
(1) a3-2a2+a=a(a2-2a+1)=a(a2-2a+1)=a(a-1)(a-1)
(2)ax2-8ax+16a =a(x2-8x=16)=a(x-4)(x-4)
(3)a3b-2a2b2+ab3 =ab(a2-2ab=b2)=ab(a-b)(a-b)