java.sql.SQLException:Parameter index out of range (1 > number of parameters,which is 0).
java.sql.SQLException:Parameter index out of range (1 > number of parameters,which is 0).
private int check(String user_name,String user_code) throws SQLException {
\x05\x05// TODO Auto-generated method stub
\x05\x05PreparedStatement stmt = null;
\x05String sql ="select * from log where name='?' and code='?';";
\x05stmt = Server.con.prepareStatement(sql);
\x05stmt.setString(1,user_name);
\x05stmt.setString(2,user_code);
\x05if(stmt.executeQuery(sql)==null){
\x05\x05return 0;
\x05}
\x05 return 1;
\x05}
String sql ="select * from log where name='?' and code='?';";改成
String sql ="select * from log where name=?and code=?“;You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? and code=?' at line 1String sql ="select * fromlog where name=? and code=?";