(log32+log23)^2-log32/log23-log23/log32
问题描述：
(log32+log23)^2-log32/log23-log23/log32
log32就是3是底数,2是真数
答
[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2)=[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2)=[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2=2/[log2(3)*log3(2)]=2为什么倒数第二步是2/啊2是平方