{3分之x+5分之y=1 (1) 3(x+y)+2(x-3y)=15 (2)

问题描述:

{3分之x+5分之y=1 (1) 3(x+y)+2(x-3y)=15 (2)
主要是过程,用加减消元

{3分之x+5分之y=1 (1) 3(x+y)+2(x-3y)=15 (2)
x/3+y/5 = 1.1
3(x+y)+2(x-3y)=15 .2
5x+3y =15.1
3x+3y+2x-6y=15
5x-3y=15.2
1+2
10x =30
x =3
5*3-3y=15
y =0
所以x = 3 y =0