已知x^2+y^2-6x-8y+25=0,求分式1/xy的值
问题描述:
已知x^2+y^2-6x-8y+25=0,求分式1/xy的值
答
x^2+y^2-6x-8y+25
= (x-3)^2+(y-4)^2
=0
x=3,y=4
1/xy=1/12