先因式分解再求值:(x+y)的平方-(x+y)(3y-x),其中x=2.5,y=-0.5

问题描述:

先因式分解再求值:(x+y)的平方-(x+y)(3y-x),其中x=2.5,y=-0.5

(x+y)²-(x+y)(3y-x)
=(x+y)(x+y-3y+x)
=(x+y)(2x-2y)
=2(x+y)(x-y)
=2(2.5-0.5)(2.5+0.5)
=12