已知x,y满足|x-2|+(y+1)²=0,求-2xy·5xy²+（½x²y²-3x）·2y+6xy的值
问题描述：
已知x,y满足|x-2|+(y+1)²=0,求-2xy·5xy²+（½x²y²-3x）·2y+6xy的值
答
|x-2|+(y+1)²=0
所以x-2=y+1=0
x=2,y=-1
所以原式=-10x²y³+x²y³-6xy+6xy
=-9x²y³
=-9×4×(-1)
=36