求解方程dy/dx+2xy+xy'=0
问题描述:
求解方程dy/dx+2xy+xy'=0
答
y=k*(e^-2x)*(x+1)^2具体过程呢y'=dy/dx.化简为(x+1)dy=-2xydx;dy/y=-2xdx/(x+1); ln(y)+c=-2x+2*ln(x+1)
求解方程dy/dx+2xy+xy'=0
y=k*(e^-2x)*(x+1)^2具体过程呢y'=dy/dx.化简为(x+1)dy=-2xydx;dy/y=-2xdx/(x+1); ln(y)+c=-2x+2*ln(x+1)