复数的三角形式及运算 （-1+√3i)^6-(-1-√3i)^6怎么算
问题描述：
复数的三角形式及运算 （-1+√3i)^6-(-1-√3i)^6怎么算
答
复数的三角形式及运算 （-1+√3i)⁶-(-1-√3i)⁶怎么算原式={2[cos(2π/3)+isin(2π/3)]}⁶-{2[cos(4π/3)+isin(4π/3)]}⁶=2⁶[cos(4π)+isin(4π)-cos(4π)-isin(4π)]=0...