解不等式:
问题描述:
解不等式:
1、(x-1)(x-2)(x-3)(x-4)>120
2、(x^2+2x-2)/(3+2x-x^2)
答
1、(x-1)(x-2)(x-3)(x-4)>120 (x-1)(x-2)(x-3)(x-4)>120 (x-1)(x-4)(x-2)(x-3)>120 (x^2-5x+4)(x^2-5x+6)>120 (x^2-5x)^2+10(x^2-5x)+24-120>0 (x^2-5x)^2+10(x^2-5x)-96>0 (x^2-5x+16)(x^2-5x-6)>0 因为x^2-5x+16>0...