log2(6)*log3(6)-[log2(3)+log3(2)]的值
问题描述:
log2(6)*log3(6)-[log2(3)+log3(2)]的值
答
loga(b)=1/logb(a) 原式=log2(2*3)*log3(2*3)-[log2(3)+log3(2)]=[log2(2)+log2(3)]*[(log3(2)+log3(3)]-[log2(3)+log3(2)]=[1+log2(3)]*[(log3(2)+1]-[log2(3)+log3(2)]=log3(2)+1+log2(3)*log3(2)+log2(3)-log2(3)...