(1/a+1/b)除以a^2+2ab+b^2/a+b,其中a=-3,b=2
问题描述:
(1/a+1/b)除以a^2+2ab+b^2/a+b,其中a=-3,b=2
答
(1/a+1/b)除以a^2+2ab+b^2/a+b
=(a+b)/ab÷(a+b)^2/(a+b)
=1/ab
=1/(-3x2)
=-1/6