a x a - (a-8) x (a-5) = 129怎么算,
问题描述：
a x a - (a-8) x (a-5) = 129怎么算,
答
a x a - (a-8) x (a-5) = 129 a^2-a^2+13a-40=129 13a=129+40 a=169/13 a=13
a x a - (a-8) x (a-5) = 129怎么算,
a x a - (a-8) x (a-5) = 129 a^2-a^2+13a-40=129 13a=129+40 a=169/13 a=13