根号2·cos(x-2/π)化简为sin(~)的形式
问题描述:
根号2·cos(x-2/π)化简为sin(~)的形式
答
由sinx=cos(π/2-x)
2·cos(x-2/π)=2·sin(π/2-(x-2/π))=2·sin(π/2-x+2/π)=2·sin(π/2+2/π-x)