化简:(2x-y)^2-2(2x-y)(2x+y)+(2x+y)^2,并求当|x+2y-1|+(2x-y-2)^2=0,代数式值
问题描述：
化简:(2x-y)^2-2(2x-y)(2x+y)+(2x+y)^2,并求当|x+2y-1|+(2x-y-2)^2=0,代数式值
答
|x+2y-1|+(2x-y-2)^2=0|x+2y-1=0,+(2x-y-2)^2=0x+2y-1=02x-y-2=0解得x=1y=0(2x-y)^2-2(2x-y)(2x+y)+(2x+y)^2=[(2x-y)-(2x+y)]^2=(2x-y-2x-y)^2=(-2y)^2=4y^2=4*0^2=0