化简:tan(π/8)+1/tan(π/12)

问题描述:

化简:tan(π/8)+1/tan(π/12)

tanα=sinα/cosα
=2s²inα/(2sinαcosα﹚
=[1-cos(2α﹚]/sin﹙2α﹚
∴tan(π/8)=√2-1
1/tan(π/12)=2+√3
∴tan(π/8)+1/tan(π/12)=√2+√3+1