已知|x+2y+1|+(-y-2)²=0,求(2x-y)²-2(2x-y)(x+2y)²
问题描述：
已知|x+2y+1|+(-y-2)²=0,求(2x-y)²-2(2x-y)(x+2y)²
答
|x+2y+1|+(-y-2)²=0
∴x+2y+1=0
-y-2=0
∴x=3
y=-2
(2x-y)²-2(2x-y)(x+2y)²
=(6+2)²-2(6+2)(3-4)²
=64-16
=48