[6(x+2)-8(x+2)(x-2)+10(x+2)]/2(x+2)怎么做
问题描述:
[6(x+2)-8(x+2)(x-2)+10(x+2)]/2(x+2)怎么做
答
[6(x+2)-8(x+2)(x-2)+10(x+2)]/2(x+2)
=6(x+2)/2(x+2)-8(x+2)(x-2)/2(x+2)+10(x+2)/2(x+2)
=3-4(x-2)+5
=16-4x