求不定积分：根号下[(1-x) / (1+x)] dx
问题描述：
求不定积分：根号下[(1-x) / (1+x)] dx
答
(1/3)*((1-x)/(1+x))^(3/2)
答
∫√[(1-x)/（1+x)]dx
=∫(1-x)/√(1-x^2)dx
=∫1/√(1-x^2)-∫x/√(1-x^2)dx
=arcsinx+1/2∫(1-x^2)^(-1/2)d(1-x^2)
=arcsinx+√(1-x^2)+c
c是常数