y=sin^2x-根号3sinxcosx-cos^2x化简
问题描述：
y=sin^2x-根号3sinxcosx-cos^2x化简
答
y=-(cos²x-sin²x）-√3sinxcosx=-cos2x-(√3/2)sin2x=-sin(2x+π/6)或者
y=-(cos²x-sin²x）-√3sinxcosx=-cos2x-(√3/2)sin2x=-cos(2x-π/3)