3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
问题描述：
3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
答
3（X-3）+10（2/3+Y）=13, ①22（X-3）+5（2/3+Y）=27②①-②×23(x-3)+10(2/3+y)-44(x-3)-10(2/3+y)=13-54-41(x-3)=-41x-3=1x=43×4+10(2/3+y)=1310(2/3+y)=12/3+y=1/10y=-17/30∴x=4,y=-17/30