[3x^2-(x+y)(y-x)][2(-x-y)(y-x)+2x^2+3y^2]怎么化简?

问题描述:

[3x^2-(x+y)(y-x)][2(-x-y)(y-x)+2x^2+3y^2]怎么化简?

[3x^2-(x+y)(y-x)][2(-x-y)(y-x)+2x^2+3y^2] =(3x^2+x^2-y^2)(2x^2-2y^2+2x^2+3y^2) =(4x^2-y^2)(4x^2+y^2) =16x^4-y^4