计算：(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)
问题描述：
计算：(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)
不好意思刚才那道弄错了 这道绝对没错
答
(x-1)/(x^2+3x-2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/[(x+1)(x+2)]-6/[(x+1)(x-2)]-(x-10)/[(x+2)(x-2)]=(x-1)(x-2)/[(x-2)(x+1)(x+2)]-6(x+2)/[(x+2)(x-1)(x-2)]-(x-10)/[(x-2)(x+2)]=(x^2-3x+2-6x-12)/[(x-1)(x+2)...