the line y=3x+k is tangent to the curve x^2+xy+16=0 find possible values of k
问题描述：
the line y=3x+k is tangent to the curve x^2+xy+16=0 find possible values of k
答
直线 y=3x+k与曲线x^2+xy+16=0相切,求 k 的可能值.
is tangent to: 与.相切没有问你是什么意思，问你怎么做。。。。。。不过还是谢谢x^2 + x(3x+k) + 16 = x^2 + 3x^2 + kx + 16 =04x^2 + kx + 16 = 0(2x + 4 )^2 = 4x^2 +16x+ 16 = 0k = 16 ; k 的可能值