24.一体积为0.25分米3,质量为2千克的铜球(ρ=8.9×103千克/米3)则判断它是 .(“实心”或“空心”)
问题描述:
24.一体积为0.25分米3,质量为2千克的铜球(ρ=8.9×103千克/米3)则判断它是 .(“实心”或“空心”)
答
铜球密度=2÷0.25=8×103千克/米3
24.一体积为0.25分米3,质量为2千克的铜球(ρ=8.9×103千克/米3)则判断它是 .(“实心”或“空心”)
铜球密度=2÷0.25=8×103千克/米3