已知a2-ab=20,ab-b2=-12,则a2-b2=_,a2-2ab+b2=_.
问题描述:
已知a2-ab=20,ab-b2=-12,则a2-b2=______,a2-2ab+b2=______.
答
∵a2-ab=20,ab-b2=-12,
∴a2-b2=a2-ab+ab-b2=20-12=8;a2-2ab+b2=a2-ab-ab+b2=20+12=32.
故答案为:8;32.