In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.
问题描述：
In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
答
kQq/r²=mv²/rk=9×10^9N·m²/C²Q=q=1.6×10^-19Cm=9.1×10^-31kgr=kQq/mv²（速度不对吧,那么慢的电子,怎么也该是它的几十万、上百万倍）（先按2×10^6m/s算）= 6.3×10^-11m=63pm...