若|3a+4b-c|+1/4(c-2b)2=0,则a:b:c=_.

问题描述:

若|3a+4b-c|+

1
4
(c-2b)2=0,则a:b:c=______.

依题意得:|3a+4b-c|=0,且(c-2b)2=0,

c=2b①
3a+4b-2b=0②

∴由②得3a=-2b,即a=-
2
3
b,
∴a:b:c=-
2
3
b:b:2b=-2:3:6.
故答案为:-2:3:6.