初二· 解·分式方程·
问题描述：
初二· 解·分式方程·
x-4/x-5 + x-8/x-9 = x-7/x-8 +x-5/x-6
简便方法计算
答
x-4/x-5 + x-8/x-9 = x-7/x-8 +x-5/x-6 =1+ 1/(x-5) + 1 +1/(x-9)=1+ 1/(x-8)+ 1 +1/(x-6) 1/(x-5) +1/(x-9)=1/(x-8) +1/(x-6)1/(x-5)- 1/(x-8)=1/(x-6) -1/(x-9)-3/(x-5)(x-8)=-3/(x-6)(x-9)x^2-13x+40=x^2-15x+542...