若集合M={α |sinα≥1/2,0≤α≤π),N={α |cosα≤1/2,0≤α≤π},求M∩N.
问题描述:
若集合M={α |sinα≥1/2,0≤α≤π),N={α |cosα≤1/2,0≤α≤π},求M∩N.
答
M={α |sinα≥1/2,0≤α≤π}=[π/6,5π/6],
N={α |cosα≤1/2,0≤α≤π}=[0,π/3],
∴M∩N=[π/6,π/3].