根号下(2+2sin(2π-θ)-cos^2(π+θ))可化简为
问题描述:
根号下(2+2sin(2π-θ)-cos^2(π+θ))可化简为
答
(2+2sin(2π-θ)-cos^2(π+θ))
=2-2sinθ+cos^2θ
=2-2sinθ+1-sin^2θ
=3-2sinθ-sin^2θ