s^2+10s+25= 9分之1x^2-3分之2x+1= 2分之1a^2+2ab+2b^2=

问题描述:

s^2+10s+25= 9分之1x^2-3分之2x+1= 2分之1a^2+2ab+2b^2=

s^2+10*s+25=(s+5)^2
9分之1x^2-3分之2x+1=(1/3x-1)^2
2分之1a^2+2ab+2b^2=((根号2a)/2+(根号2))^2