(1×3×11+2×6×22+3×9×33)/ 1×2×17+2×4×34+3×6×51
问题描述:
(1×3×11+2×6×22+3×9×33)/ 1×2×17+2×4×34+3×6×51
答
原式=[1x3x11+2x(1x3x11)+3x(1x3x11)]/[1x2x17+2x(1x2x17)+3x(1x2x17]
=(1x3x11)x(1+2+3)/(1x3x17)x(1+2+3)
=1x3x11/1x2x17
=33/34