（2a+1/2a-1）除以{1除以（1-1/a +1/4a平方）}除以（1-1/2a+1） 计算是中国人就给我回答

原式=[(2a+1)/(2a-1)]÷{[1÷(1-1/2a)^2]÷[(2a+1-1)/(2a+1)]}
=[(2a+1)/(2a-1)]÷{1÷[(2a-1)/2a]^2}÷[2a/(2a+1)]
=[(2a+1)/(2a-1)]÷{[4a^2/(2a-1)^2]÷[2a/(2a+1)]}
=[(2a+1)/(2a-1)]÷[4a^2(2a+1)/(2a-1)^2*2a]
=[(2a+1)/(2a-1)]÷[a(2a+1)/(2a-1)^2]
=(2a+1)(2a-1)^2/[(2a-1)a(2a+1)]
=(2a-1)/a