计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)

问题描述:

计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)

[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)
=(-1/4a^4·x^2+1/3a^2·x^3)÷(1/6ax)
=-3/2a^3·x+2a·x^2[-(1/2a²x)²+(1/3ax²×ax)]÷(-1/6ax)题目弄错了,麻烦在看下[-(1/2a²x)²+(1/3ax²×ax)]÷(-1/6ax)=(-1/4a^4·x^2+1/3a^2·x^3)÷(-1/6ax)=3/2a^3·x-2a·x^2