5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,
问题描述:
5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,
答
5a²+[a²+(5a²-3a²)-6(a²-a)],=5a²+(a²+2a²-6a²+6a)=5a²+a²+2a²-6a²+6a=2a²+6a=2*1/4+6*(-1/4)=1/2-3/2=-1