lga-lgb=lg( a / b)
问题描述:
lga-lgb=lg( a / b)
lga+lgb=lg( a X b)
lga X lgb=?
lga / lgb=?
答
lga×lgb=lg(b^lga)=lg(a^lgb)
lga÷lgb=logb(a)lg(b^lga)=lg(a^lgb)????恩采纳吧