x-1分之x-2除以(x+1 -x-1分之3),其中x=根号3-2

问题描述:

x-1分之x-2除以(x+1 -x-1分之3),其中x=根号3-2

答:
[(x-2)/(x-1)]÷[x+1-3/(x-1)]
=[(x-2)/(x-1)]÷[(x²-1-3)/(x-1)]
=[(x-2)/(x-1)]×(x-1)/(x²-4)
=1/(x+2)
=1/(√3-2+2)
=√3/3